**The Boron MPA**

The boron MPA is a face-centred cubic array of six funnels projecting from a central globe. A funnel contains an Ad6 group and four ovoids, each of which contains two hydrogen triplets (H3). The globe has four spheres, each enclosing groups of five UPAs (B5).

**Boron MPA = 4B5 + 6[4(((2H3) +
Ad6].**

Central globe & a funnel of the boron MPA.

The MPA is formed from two B^{11} nuclei, which provide 198 subquarks, i.e., two
fewer than the number of UPAs. The twenty-four d quarks present in the twelve neutrons of both nuclei are the pairs
of triplets in two ovoids in each funnel, the two other ovoids containing pairs of u quarks. These quark pairs are
not diquarks because the quarks are bound not by strings but by the residual coupling between the strings binding
their subquarks; they are the quark counterpart of the deuteron. That u and d quarks make up the ovoids is
confirmed by the disintegration diagram, which shows that twenty-four (+) triplets and twenty-four (−) triplets (d
quarks) are released from the funnels at the E3 stage of

disintegration. The diagram does not indicate whether the triplets in an ovoid are either both
(+) or both (−) (as assumed above) or whether they consist of one of each type (the 1st edition of *Occult
Chemistry* sheds no light on this matter). There is no stronger theoretical reason to make the former
choice than that the pairs of d quarks supplied by the twelve neutrons in the two B^{11} nuclei
remained together during the formation of the boron MPA.

The six Ad6 groups consist of three u-u diquarks and three d-d diquarks. The disintegration diagram confirms that there are three (+) Ad6 groups, which break up at the E2 stage into six (+) triplets (u quarks) and three (−) Ad6 groups, which split into six (−) triplets (d quarks).

The central globe is predicted to contain two B5 groups and two quartets of UPAs, not the observed four B5 groups. They consist of the eight X subquarks and ten Y subquarks making up the two u quarks and four d quarks remaining in the two nuclei after their thirty u quarks and thirty d quarks were released as pairs of H3 triplets or Ad6 groups. These subquarks regroup to form two B5 groups (3X-2Y) and two X-3Y bound states (Li4):

2u (= 2X-Y) + 4d (= X-2Y) = 8X + 10Y → 2(3X-2Y) + 2(X-3Y).

Alternatively, one B5 group could be the mirror state B5′ (2X-3Y), in which case the two quartets cannot be the same but, instead, consist of an X-3Y bound state (Li4) and a 2X-2Y bound state (Be4). The disintegration diagram confirms that one B5 group is a 3X-2Y bound state because it indicates that the group breaks up into a (−) triplet (d quark) and a (+) duad (X-X):

3X-2Y → d (= X-2Y) + X-X.